-y^2-16y+14=0

Solution for -y^2-16y+14=0 equation:

-y^2-16y+14=0

We add all the numbers together, and all the variables

-1y^2-16y+14=0

a = -1; b = -16; c = +14;
Δ = b2-4ac
Δ = -162-4·(-1)·14
Δ = 312
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{312}=\sqrt{4*78}=\sqrt{4}*\sqrt{78}=2\sqrt{78}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-2\sqrt{78}}{2*-1}=\frac{16-2\sqrt{78}}{-2}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+2\sqrt{78}}{2*-1}=\frac{16+2\sqrt{78}}{-2}
$